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IGCSE Physics, Cambridge 0625, Malaysia

How to Show Working in IGCSE Physics Calculations

The exact steps examiners look for when awarding method marks in calculation questions, with examples of full working.

Written by IGCSEPhysics Content Team · Physics subject adviser: K. S. Tan, 15+ years teaching IGCSE Physics · Checked against the Cambridge IGCSE Physics (0625) 2026 to 2028 syllabus

Use this guide to present calculation working that earns maximum method marks in Cambridge IGCSE Physics 0625 exams.

Why showing working matters

In a 3-mark calculation, the marks are typically split:

  • 1 mark for writing the correct formula
  • 1 mark for correct substitution
  • 1 mark for the correct final answer with unit

If you skip the formula and substitution, then make a calculator error, you score 0 out of 3. If you show full working, the same calculator error costs you only the final mark: you still get 2 out of 3.

The four-step method

Step 1: Write the formula

Write the equation from memory or the equation sheet. Use standard symbols.

Example: v = s / t

Step 2: Substitute the values

Replace each symbol with the number from the question. Include units at this stage.

Example: v = 120 m / 30 s

Step 3: Calculate

Perform the arithmetic. Show intermediate steps if the calculation involves rearrangement.

Example: v = 4 m/s

Step 4: State the answer with its unit

Write the final answer clearly. Circle it or underline it so the examiner can find it.

Example: v = 4 m/s

Worked example: Specific heat capacity (4 marks)

Question: A 2.0 kg block of aluminium is heated from 20 degrees C to 70 degrees C. The energy supplied is 90 000 J. Calculate the specific heat capacity of aluminium.

Working:

E = m c (change in T)

change in T = 70 - 20 = 50 degrees C

c = E / (m x change in T)

c = 90 000 / (2.0 x 50)

c = 90 000 / 100

c = 900 J/(kg degrees C)

Mark allocation: formula (1), substitution (1), change in T correct (1), final answer with unit (1).

Worked example: Electrical power (3 marks)

Question: A lamp has a resistance of 12 ohm and a current of 2.5 A flowing through it. Calculate the power dissipated by the lamp.

Working:

P = I^2 x R

P = (2.5)^2 x 12

P = 6.25 x 12

P = 75 W

Common mistakes in showing working

  • Forgetting the unit in the final answer. This is typically a separate mark.
  • Using the wrong version of the formula and not showing the rearrangement.
  • Mixing up units (using grams instead of kilograms, minutes instead of seconds).
  • Writing the answer without enough significant figures or with too many.

Significant figures

The general rule: give your answer to the same number of significant figures as the data in the question, or to 2 or 3 significant figures, whichever is appropriate. Never round intermediate steps; only round the final answer.

Frequently Asked Questions

Can I skip the formula and go straight to the numbers?
You can, but you lose the method mark for writing the formula. If your final answer is wrong, showing the formula gives you a chance at partial credit.
Do I need to show every line of algebra?
Show enough that the examiner can follow your reasoning. You do not need to show trivial arithmetic like 6 times 3 = 18, but you should show substitution and rearrangement steps.
What if I get the right answer but show no working?
For a 1-mark calculation, you usually get the mark. For a 3-mark or 4-mark calculation, you will get the final-answer mark but lose the method marks. This means if you make a small error, you get zero instead of partial credit.

Next useful steps

Need Help Applying This?

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