Skip to content
IGCSE Physics, Cambridge 0625, Malaysia
Supplement only

Archimedes' Principle and Upthrust

The upthrust on a submerged object equals the weight of the fluid displaced, explaining why objects float or sink.

Written by IGCSEPhysics Content Team · Physics subject adviser: K. S. Tan, 15+ years teaching IGCSE Physics · Checked against the Cambridge IGCSE Physics (0625) 2026 to 2028 syllabus

Archimedes’ principle states that the upthrust (buoyant force) on an object submerged in a fluid equals the weight of the fluid displaced.

Fupthrust=ρfluid×g×VdisplacedF_{\text{upthrust}} = \rho_{\text{fluid}} \times g \times V_{\text{displaced}}

Floating and sinking

An object floats when the upthrust equals its weight:

ρfluidgVsubmerged=mg\rho_{\text{fluid}} g V_{\text{submerged}} = mg

For a floating object, the fraction submerged equals the ratio of densities:

VsubmergedVtotal=ρobjectρfluid\frac{V_{\text{submerged}}}{V_{\text{total}}} = \frac{\rho_{\text{object}}}{\rho_{\text{fluid}}}

An object sinks if its density is greater than the fluid’s density (ρobject>ρfluid\rho_{\text{object}} > \rho_{\text{fluid}}).

Measuring density using Archimedes’ principle

For an irregularly shaped object:

  1. Weigh the object in air: WairW_{\text{air}}.
  2. Weigh the object fully submerged in water: WwaterW_{\text{water}}.
  3. Upthrust =WairWwater=ρwatergV= W_{\text{air}} - W_{\text{water}} = \rho_{\text{water}} g V.
  4. V=WairWwaterρwatergV = \frac{W_{\text{air}} - W_{\text{water}}}{\rho_{\text{water}} g}.
  5. ρobject=mV\rho_{\text{object}} = \frac{m}{V}.

Common errors and how to correct them

  • Confusing the weight of fluid displaced with the weight of the object.
  • Forgetting that upthrust depends on the volume submerged, not the total volume (for partially submerged objects).

How to apply this in an exam

State Archimedes’ principle. Identify the displaced volume. Calculate the upthrust. Compare upthrust with weight to determine floating/sinking.

Need help with this concept?

A 0625 specialist can work through the student's current question and help identify whether the difficulty is the concept, the calculation or the exam technique.