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IGCSE Physics, Cambridge 0625, Malaysia
Core + Supplement sections

Light: Reflection, Refraction, Total Internal Reflection and Lenses

Light for IGCSE Physics 0625: plane mirrors, refractive index, total internal reflection and lens ray diagrams, with a worked Snell's law question.

Written by IGCSEPhysics Content Team · Physics subject adviser: K. S. Tan, 15+ years teaching IGCSE Physics · Checked against the Cambridge IGCSE Physics (0625) 2026 to 2028 syllabus

This lesson explains Light: Reflection, Refraction, Total Internal Reflection and Lenses for Cambridge IGCSE Physics 0625. It separates the Core requirements from the additional Supplement work for Extended candidates. Focus on the cause-and-effect explanation and the exact quantities being compared. After the example, use the related practice questions to check what you can do independently.

What are the rules for reflection and refraction of light?

Reflection: the angle of incidence equals the angle of reflection, both measured from the normal. The image in a plane mirror has four properties: same size as the object, same distance behind the mirror as the object is in front, virtual (cannot be formed on a screen), and laterally inverted. All four are standard recall marks.

Refraction: light bends towards the normal when it slows down entering a denser medium (air to glass), and away from the normal when it speeds up leaving. Extended candidates quantify this with refractive index.

QuantitySymbolUnit
Angle of incidenceiidegree (°)
Angle of refractionrrdegree (°)
Critical angleccdegree (°)
Refractive indexnnno unit

In words: refractive index = sine of the angle of incidence ÷ sine of the angle of refraction. In symbols: n=sinisinrn = \dfrac{\sin i}{\sin r}. The critical-angle relationship: n=1sincn = \dfrac{1}{\sin c}.

Total internal reflection happens when light inside the denser medium hits the boundary at an angle greater than the critical angle. All the light reflects back inside. Optical fibres exploit this to carry telephone and broadband signals as light pulses bouncing along a glass core. White light passing through a prism disperses into a spectrum because each colour refracts by a different amount. Light of a single frequency is called monochromatic.

How do you draw lens ray diagrams that score the available marks?

A thin converging lens brings parallel rays to a focus at the principal focus, F. The distance from lens to F is the focal length. Use two construction rays from the top of the object: one parallel to the axis, refracting through F; one straight through the centre of the lens. Where they cross, the image forms. Object beyond F: image is real and inverted. Object closer than F: the rays diverge, and tracing them backwards gives an enlarged, upright, virtual image (the magnifying glass). Extended candidates also link lenses to vision: a diverging lens corrects short-sightedness; a converging lens corrects long-sightedness.

Worked example

A ray of light passes from air into glass. The angle of incidence is 45° and the angle of refraction is 28°. (a) Calculate the refractive index of the glass. [2] (b) Calculate the critical angle of the glass. [2]

Worked solution:

  1. (a) Equation: n=sinisinrn = \dfrac{\sin i}{\sin r}
  2. Substitute: n=sin45÷sin28=0.7071÷0.4695n = \sin 45^\circ \div \sin 28^\circ = 0.7071 \div 0.4695
  3. Answer: n=1.5n = 1.5 (2 significant figures)
  4. (b) Equation: n=1sincn = \dfrac{1}{\sin c}, so sinc=1÷1.5=0.667\sin c = 1 \div 1.5 = 0.667; c=sin1(0.667)=42c = \sin^{-1}(0.667) = 42^\circ (2 significant figures)

Original marking points:

  • M1: n=sinisinrn = \dfrac{\sin i}{\sin r} with correct substitution
  • A1: 1.5 (accept 1.51; no unit)
  • M1: sinc=1n\sin c = \dfrac{1}{n} used (error carried forward allowed)
  • A1: 4242^\circ

These marking points belong to this original example. They are not an official Cambridge mark scheme.

Common errors and how to correct them

  • Measuring angles from the mirror or glass surface. Every angle is measured from the normal; mislabelled angles void the calculation.
  • Forgetting the sines and computing i÷ri \div r. 45÷2845 \div 28 gives 1.6, close enough to look right and still wrong (you must take the sines first).
  • Giving refractive index a unit. It is a ratio of sines and has no unit.
  • Drawing ray diagrams without arrows, or construction lines freehand. Arrows and ruler-straight rays are explicit mark-scheme requirements.
  • Calling the plane-mirror image real. It is virtual, because no rays actually meet behind the mirror.

How to apply this in an exam

Set your calculator to degrees before the exam starts, and check it on every paper. A calculator left in radians turns sin45\sin 45^\circ into 0.851 and quietly destroys both marks. Then follow the routine: equation, substitution with the sine values written out, answer to 2 significant figures. Writing the intermediate sine values earns method marks even when the final keystroke slips.

Where this skill matters

Light is relevant to paper, usually for more marks than any other Waves subtopic. Papers 1 and 2 test mirror-image properties, refraction direction and lens facts. Papers 3 and 4 demand ray diagrams and, on Extended only, the n=sinisinrn = \dfrac{\sin i}{\sin r} and n=1sincn = \dfrac{1}{\sin c} calculations, plus virtual-image lens constructions and sight correction. Core candidates describe total internal reflection qualitatively. Papers 5 and 6 feature the classic pins-and-glass-block or lens-and-screen experiments: tracing rays, measuring angles, finding focal length. There is a lot here, so it helps to study diagrams first and calculations second rather than mixing the two in one sitting.

Key concepts in Light

Work through each concept below. Every page explains the idea, the common exam mistakes and the calculation steps that earn marks.

Still unsure about Light?

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