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IGCSE Physics, Cambridge 0625, Malaysia
Core

Calculating the Cost of Electricity

Using the kilowatt-hour (kWh) to calculate the energy consumed by appliances and the cost of electricity.

Written by IGCSEPhysics Content Team · Physics subject adviser: K. S. Tan, 15+ years teaching IGCSE Physics · Checked against the Cambridge IGCSE Physics (0625) 2026 to 2028 syllabus

Electricity bills are calculated using the kilowatt-hour (kWh), not the joule.

The kilowatt-hour

E(kWh)=P(kW)×t(h)E(\text{kWh}) = P(\text{kW}) \times t(\text{h})

1 kWh is the energy transferred by a 1 kW device operating for 1 hour.

1 kWh=1000 W×3600 s=3,600,000 J=3.6 MJ1 \text{ kWh} = 1000 \text{ W} \times 3600 \text{ s} = 3{,}600{,}000 \text{ J} = 3.6 \text{ MJ}

Calculating energy used

Example: A 2.5 kW oven runs for 1.5 hours.

E=2.5×1.5=3.75 kWhE = 2.5 \times 1.5 = 3.75 \text{ kWh}

Calculating cost

cost=E(kWh)×price per kWh\text{cost} = E(\text{kWh}) \times \text{price per kWh}

If electricity costs RM 0.40 per kWh:

cost=3.75×0.40=RM 1.50\text{cost} = 3.75 \times 0.40 = \text{RM } 1.50

Comparing appliance running costs

AppliancePower (kW)Time used per day (h)Energy per day (kWh)
LED bulb0.0180.08
Laptop0.0660.36
Kettle2.00.250.50
Air conditioning1.51015.0

The air conditioning uses far more energy despite having a lower power rating than the kettle, because it runs for much longer.

Common errors and how to correct them

  • Using watts instead of kilowatts (divide by 1000 first).
  • Using seconds instead of hours.
  • Forgetting to multiply by the price per unit.

How to apply this in an exam

Convert power to kW and time to hours. Multiply for energy in kWh. Multiply by the cost per unit. Show each step clearly.

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