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IGCSE Physics, Cambridge 0625, Malaysia
Core + Supplement

Electrical Power and Energy Calculations

Calculate electrical power using P = IV, P = I^2R and P = V^2/R, and calculate energy transferred using E = Pt and E = IVt.

Written by IGCSEPhysics Content Team · Physics subject adviser: K. S. Tan, 15+ years teaching IGCSE Physics · Checked against the Cambridge IGCSE Physics (0625) 2026 to 2028 syllabus

Electrical power is the rate at which energy is transferred by an electrical component.

Power equations

P=IVP = IV

Combining with V=IRV = IR gives two additional forms:

P=I2RP=V2RP = I^2R \qquad P = \frac{V^2}{R}

SymbolQuantityUnit
PPPowerW
IICurrentA
VVPotential differenceV
RRResistanceΩ\Omega

Energy transferred

E=Pt=IVtE = Pt = IVt

SymbolQuantityUnit
EEEnergy transferredJ
ttTimes

Worked example: power

A 230 V kettle draws a current of 10 A. Calculate the power.

P=IV=10×230=2300 W=2.3 kWP = IV = 10 \times 230 = 2300\text{ W} = 2.3\text{ kW}

Worked example: energy

The kettle runs for 3.0 minutes. Calculate the energy transferred.

t=3.0×60=180 st = 3.0 \times 60 = 180\text{ s}

E=Pt=2300×180=414000 J=414 kJE = Pt = 2300 \times 180 = 414\,000\text{ J} = 414\text{ kJ}

Choosing the right equation

Known valuesUse
II and VVP=IVP = IV
II and RRP=I2RP = I^2R
VV and RRP=V2/RP = V^2/R

Common errors and how to correct them

Using the wrong power equation. Choose based on which two quantities you know. If you have VV and RR but not II, use P=V2/RP = V^2/R directly rather than finding II first (though both methods work).

Forgetting to square the current in P=I2RP = I^2R. The II is squared, not just multiplied. P=I2RP = I^2R is not the same as P=IRP = IR.

How to apply this in an exam

Write the equation you are using, substitute, and calculate. Convert time to seconds for energy calculations. State the unit (W for power, J for energy).

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